please help?
1) if A = B.T/ R + z…. solve for B
2) if y+4/6 = x … solve for y in terms of x
3) write the equation of a line that contains the points ( 6,5) , ( 9,11) …
4) x^2 – 8 = 28 ( solve one variable)
|x – 4| = 12
|3x – 4| when x = -2
10 points for the best answers
Favorite Answer
A = B*T/R + Z
A – Z = B*T/R
R*(A-Z)=B*T
B=R/T*(A-Z)
2) Same thing as 1.
y+4/6=x
y=x-4/6
3) ok, a toughie!
first, you want to find the slope:
(11-5)/(9-6) = 6/3 = 2
now put into slope-intercept form, y=mx+b
y=2x+b, now find y-intercept (b)
5=2(6)+b
b=5-12
b=-7
now plug back into equation, y=mx+b
y=2x-7
4) not too bad…
x^2 – 8 = 28
x^2 = 28+8
x^2 = 36
x = sqrt(36)
x=plus/minus 6
x=6
5) easy…
|x – 4| = 12
(x – 4) = plus/minus 12
x = 12 + 4 OR x = -12 + 4
x=16 OR x=-8
6) i guess you just evaluate…
|3x – 4|
|3(-2) – 4|
|-6 – 4|
|-10|
=10
4. (6) 6^2 – 8 = 28
5. (x=16 or x=-8)
6. (10) |-6-4| = |-10| = 10
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