A few days ago

09chick

physics questions please help it will be appreciated?

1)A bus slows down uniformly from 72.1 km/h to 0 km/h in22.6 seconds.How far does it travel before stopping ?answere in units of m.

range betwee{168.333-275.283}

2)A car accelerates from rest at -3.05 m/s squared.

a)What is the velocity at the end of 6.4 seconds?answere in unit m

Range {-31.52 to -8.241}

b)What is the displacement after 6.4 seconds?answere in units of m

Range {-126.08 to -16.64}

3)A car traveling at 7.1 m/s acclerates 2.2 m/s squared to reach a speed of 11.0 m/s.

How long does it take for this acceleration to occur ?answere in units of s.

Range {0.568182 -5}

Thank you so much.I need the help and i need to get this homework done .

Top 1 Answers

A few days ago

³√carthagebrujah

Favorite Answer

1: Use the basic distance equation given velocity, acceleration, and time:

d = vi * t + 1/2at²

Convert 72.1 km/h to m/s:

72.1 km / h * 1000 m / 1 km * 1 h / 3600 s = 20.03 m/s

Find a:

a = Δv/t = -20.03 / 22.6 = -0.886 m/s²

Plug everything in:

d = 20.03 m/s * 22.6 s + 1/2 * -0.886 m/s² * 510.76 s² =

452.678 m + -226.26668

d = 226.4 m

2a.) To find the acceleration, use v = at.

v = -3.05 m/s² * 6.4 s = -19.52m/s²

2b.) Displacement can be found using the same formula as in 1.

3. Again, use v = at, but use algebra to isolate t:

Δv = at

Δv/a = at/a

Δv/a = t

Δv = 11.0 – 7.1 = 3.9 m/s

3.9 m/s / 2.2 m/s² = 1.773 s.

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