Physics hw please help me.?
2.) Observations are made of a distant television tower from each end of a 100-m base line. From each position the angle between the line of sight and the base line is 85.5 degrees. How far is the tower from the center of the line?
Favorite Answer
If the ball is projected with velocity v at angle x to the horizontal and t is the time of flight, then:
0 = v sin(x) – gt / 2 …(1)
s = tv cos(x) …(2)
Eliminating t:
s = 2v^2 sin(x)cos(x) / g
s = v^2 sin(2x) / g
If the distances are s1 with x = 30deg, and s2 with x = 45deg, then:
s2 – s1
= v^2 (sin(90) – sin(60)) / g
= 75^2 (1 – sqrt(3)/2)) / 9.81
= 76.82m.
2.
Let A be one end of the base line, C be the base of the tower, B be the mid-point of the baseline.
Triangle ABC:
AB = 50m
BC / AB = tan(85.5)
Hence:
BC = 50tan(85.5) = 635.3m.
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles