Physical Science Help Please…?

Suppose 6L of a gas initially at 120K and 3atm, is put under conditions of 300K and 0.6atm. What is the new volume?

If you could show me the formula you used that would be great, thanks!

Top 1 Answers

A few days ago

zack

Favorite Answer

PV=nRT

n=1 mol

R= 0.0805 (L atm) / (mol K)

T= 300K

P=0.6 atm

(0.6 atm) V = 1 (0.0805 (L atm) / (mol K)) (300K)

V= ((0.0805 (L atm) / (mol K)) (300K)) / (0.6 atm)

V= (0.0805 * 300) / (0.6)

V= 40.25 L

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