A few days ago
sweet_carofine

Permutation.. combination… probability!!! HELP!?

“IN a family of 6 children what is the probablity of having 3 boys and 3 girls?” The best answer should explain how to get the answer and why i use permutation and/or combination… i guess ill start by stating that ive probably got to figure out how many possibilities there are with 6 children or something…ldksf HELP

Top 2 Answers
A few days ago
Aquaboy

Favorite Answer

I’m pretty sure you have to use combination, and not permutation, because although you have distinct sets of objects, the individual elements in the subsets are not treated as distinct, and order is of no importance, (i.e. The order of birth doesn’t matter, and nothing distinguishes any differences between two boys or two girls). That’s why you should use combination…though I’m not too sure how…

But in this case, because of the relatively small sample space, you don’t necessarily have to rely on formulas. For example:

Let’s let g = girl, and b = boy, then your sample space, S, is:

S = {6b0g, 5b1g, 4b2g, 3b3g, 2b4g, 1b5g, 0b6g}

As you can see, there are 7 elements in the sample space, and it is assumed that each is equally likely to occur, so the probability of each element occurring is: 1/7.

Also note that there is only one way (one element) in this sample space to obtain 3 boys and 3 girls.

Therefore, the probability of having 3 boys and 3 girls is:

1/7.

0

4 years ago
purifory
If we evaluate the three horses that end interior the dazzling 3 then there are 12c3 obtainable outcomes. there is in easy terms one mixture the place all the vendors end interior the dazzling 3 => hazard of this happening is a million/12c3=a million/220~0.0.5
0