A few days ago
lele

number problem help please!?

2 times a number, increased by 28, is less than or equal to 6 times that number.

Top 4 Answers
A few days ago
?

Favorite Answer

Let x = the number. Then

2x + 28 <= 6x 28 <= 4x 7 <= x; Therefore, x >= 7

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A few days ago
p|nky
Suppose: a = the number

2a + 28 <= 6a 28 <= 6a – 2a 28 <= 4a a >= 7

So the number has to be more than or equal to 7.

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4 years ago
meggi
x = 3y x + y = 28 => 3y + y = 28 => y = 28 / 4 = 7 x = 3y = 3*7 = 21 x = y-3 x+y = 21 =>y-3+y = 21 => 2y = 24 => y = 24/2 = 12 x = y – 3 = 12 – 3 = 9 x = y+5 2x = 3y-12 => 2(y+5) = 3y-12 => 2y + 10 = 3y – 12 => 10 + 12 = 3y – 2y => y = 22 x = y + 5 = 22 + 5 = 27
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A few days ago
nerdy_pearlita
2x + 28 ≤ 6x

28 ≤ 4x

7 ≤ x

x ≥ 7

Hope this helps!

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