A few days ago
Anonymous

Need physics help please?

A block of mass M = 3 kg is released from rest and slides down an incline that makes an angle 32° with the horizontal. The coefficient of kinetic friction between the block and the incline is µk = 0.15.

a) What is the acceleration of the block down the inclined plane?

Top 2 Answers
A few days ago
igorotboy

Favorite Answer

We’ll need F=ma to find the acceleration. We have two forces acting though – one of gravity pulling the mass down the ramp, and one of friction resisting that pull.

The force of gravity runs parallel to the ramp, so we’ll need to use some trig to find the force. Normally the force acting on the mass is

F = ma

F = (3 kg)(9.81 m/s^2)

F = 29.43 N

But since we’re on an incline, we need to find the force along the ramp:

Fg = F * sin 32

Fg = 29.43 N * sin 32

Fg = 15.6 N

The force resulting from friction requires us to use the force of the mass acting perpendicular to the ramp. So,

Fn = F * cos 32

Fn = 29.43 N * cos 32

Fn = 24.96 N

Ff = µ * Fn

Ff = 0.15 * 24.96 N

Ff = 3.73 N

So the resulting force of the block is

Fr = Fg – Ff

Fr = 15.6 N – 3.73 N

Fr = 11.87 N

Finally, we can find the acceleration:

F = ma

11.87 N = 3 kg * a

a = 3.96 m/s^2

0

A few days ago
yupp
is this HS or college coursework?
0