(2) You have to find the value of x^2 + 3x – 9 when x is (a) 4,

(b) -1 and(c) -3, so:

g(4) = 4^2 + 3*4 – 9

= 16 + 12 – 9

= 28 – 9

= 19.

g(-1) = (-1)^2 + 3*(-1) – 9

= 1 – 3 – 9

= 1 – 12

= – 11.

g(-3) = (-3)^2 + 3*(-3) – 9

= 9 – 9 – 9

= -9.

3 is correct for f(x) = x – 2

4, 5, and 6 are not clear to me.

Hope this helps, Twiggy.

BTW, it`s very refreshing to find that you have attempted the questions, and you`re not just asking for the answers. Keep on working hard ! ! !

you should know that Df in here is the whole real numbers. i mean you can put any x ni it. for example 2 , 1/2, …

so you should use the decart’s dimensions.

the same for else