Need help with geometry homework!?
Directions: You are given an equation of a line and a point. Use substitution to determine whether the point is on the line.
Problem 18~
y=5x+3; A(1,8)
Problem 19~
y= -3x -6; A(2,0)
Favorite Answer
y=5x+3; A(1,8)
8=5(1)+3
8=5+3
8=8
So that matches. So that point is on the line.
Now look at the next one.
y= -3x -6; A(2,0)
You are given an equation with x and y in it, and a point (2,0). What is the x value? 2. What is the y value? 0. Plug those into the equation.
y= -3x -6; A(2,0)
0=-3(2)-6
0=-6-6
0=-12. NO!!
So this point isn’t on the line.
18) 8 = 5(1) + 3
8 = 8 yes
19) 0 = -3(2) – 6
0 = -6 -6 no
Your test point is (x, y), so plug the test point’s x-value in for the x in the line equation and plug the test point’s y-value in for the y in the line equation.
If the equation is true, the point is on the line. If the equation is false, the point is not on the line.
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