10+2y + 3 = .2z, or 2y = .2z – 13. Use this in first:

.2z – 13 + z = 8, or 1.2z = 21, so z = 17.5

Use this in third: x+3 = .2z = 3.5, so x = .5

Use this in second: .5 – 2y = 10, or -2y = 9.5, so y = -4.75

(x,y,z)= (.5, -4.75, 17.5)

1x-2y=10 ; x = (10 + 2y) equation 2

1x+3=0.2z ; substitute the value of z & x to solve y…

therefore:

1(10 + 2y) = 0.2(8 – 2y)

y = 3.92 units

then;

Substitute the value of y to eq. 1 & eq. 2 to solve for z and x respectively…

2y=8

then divide mo s 2 kea

y=4 ANSWER

1z=8

then divide mo s 1 kea

z=8 ANSWER

same procedure….

1x=10

then divide mo s 1 kea

x=10 ANSWER

-2y=10

then divide mo s -2 kea

y=-5 ANSWER

transpose mo muna ung 3 kea mggng -3 at ung 0.2z ke -0.2z

same procedure….

1x= -3

then divide mo s 1 kea

x= -3 ANSWER

-0.2z= -3

then divide mo s -0.2 kea

z= 15 ANSWER

sna naka2long ako……