Math Question???!!? HELP!?
Instruction…Find the equation of a line that both passes through the point (-4,5) and is parallel to the line of the give equation.
(1) y= – 3x + 1
The slopes are the same if the two lines are parallel, as the other answers said.
y=mx+b, where x and y are value of each point on the line, m is the slope and b is the y-intercept, the place where the line crosses the y axis.
So in the original equation, the slope is -3. To be parallel, the slope of the new line must also be -3, so for the equation of the new line, we already know that y= -3x+b.
We also know the x and y values of a point on the new line, so let’s solve for b.
5 (the y value) = (-3)(-4) [slope times x value] +b.
5=12+b, so b= -7.
Now we have the equation of the second line: y+-3x-7.
Now you just need to find the y-intercept for the point (-4,5) which is (0,-7) i think.
Now you have everything you need so your equation should be
( 1y = -3x + 1 ) or ( y – 1 ) = -3x.
so substitute y with 4
so ( 4 – 1 ) = -3x
so x = 3/-3 = -1
so the new co-ordinates that pass through ( – 4, 5 )
is ( -1, 4 ) where x = -1 and y = 4
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