A few days ago
math problem?
how do you solve
P(p-3q)^2
?
Top 3 Answers
A few days ago
Favorite Answer
P(p-3q)^2 (I am assuming you meant lower case p)
p(p^2 – 2(p)(3q) + (3q)^2) solve the ^2 part first
p(p^2 -6pq + 9q^2) simplify
p^3 – 6p^2q + 9pq^2 distribute the first “p”
I am assuming what you want is for this equation to be fully expanded as you didn’t say to sovle p or q.
0
A few days ago
well im not sure about this are you just supposed to simplify the expression? you use order of operations so the exponent will go first. (p-3q) squared so (p-3q)(p-3q) which is p^2-3pq-3pq+9q^2. so that is (p^2-6pq+9q^2) then multiply that by the P. i dont know if P is the same as p so i will assume i dont really know if this is right in the first place but anyway………………P times the expression we got above should be if P=p it should be
(p^3-6qp^2+9pq^2)
i have no idea if that is right i did it logically way i was tought. if you have to sub the variables make sure you use the order of operations. what level math is this? sorry if that is wrong i think its right…capital P is same as small p right? just cuz it was in the beginning?
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A few days ago
if it’s P(p-3q)^2 then,
P(p^2-6pq+9q^2)
Pp^2-6Ppq+9Pq^2
but… if it is p(p-3q)^2 then,
p(p^2-6pq+9q^2)
p^3-6p^2q+9pq^2
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