Math Homework??!!!!?
The area of the semicircular region is 16 pi. Find the figure’s perimeter.
There is also a picture of a semicircle, but that’s it. We haven’t even gone over this in class and I have no idea how to start. I looked in the back of the book to find the answer to see if I could figure the answer out like that, but I still don’t know. The answer is approximately 29.09. Please show all the work. Thanks ahead of time!!!!
Favorite Answer
a = pi r^2 / 2 ….(1)
The perimeter of the semicircle is pi*r for the curved part, and 2r for the straight line. That totals r(pi + 2) …..(2)
From (1):
pi r^2 / 2 = 16 pi
r^2 / 2 = 16
r^2 = 32 = 16*2
r = sqrt(16)sqrt(2) = 4sqrt(2).
From (2), the perimeter is:
4sqrt(2) (pi + 2)
= 4 * 1.4142 * (3.14159 + 2)
= 29.09.
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