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The perimeter of a rectangle is 128m the length of is 10m more than twice the width, what are the deminsions?

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A few days ago

Anonymous

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Given: L = 2w + 10

Since two of its sides are L long, and two are w long, the following equation is true:

2L + 2w = 128 m

Substituting for L:

2(2w + 10) + 2w = 128 m

Solving for w, we find w = 18 m.

Then substituting that back into our original equation:

L = 2(18) + 10 = 46 m

So the rectangle is 46 m long and 18 m wide.

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