55+ 10=2x +3x

65= 5x

divide x to its lowest term

x=65/5

x=13

Similarly, for x+6+x=28

group the x and numbers each to one side,

x +x = 28 – 6

2x =22

now divide x to its lowest term…

x=11

now for 61=6-8x-3x

61-6= -8x-3x

55= -11x

So to get a positive x, you got to divide both side by -11

x= -5

55-3x-2x=10

+3x +3x

Then you have to deal with the two:

55-2x=10+3x

+2x +2x

55=10+5x

Then you need to do the ten:

55=10+5x

-10 -10

45=5x

Divide both sides by 5 to have just x and you get:

45/5=5x/5

9=x

Doing the same thing for the rest it should turn out liek this:

x+6+x=28

x+x=22

2x=22

x=11

And the last one:

61=6-8x-3x

55=-11x

-5=x

Hope that helps. If not email me at [email protected]

55-5x=10

then you would subtract the 55 from both sides ending up with:

-5x=-45

now you would divide the -5 from both sides resulting in:

x=9

The second one you would add the x’s together making 2x. the equation would look like this:

2x+6=28

now you would subtract the 6 from both sides making:

2x=22

lastly you would divide the 2 from both sides resulting in:

x=11

the last equation, you would subtract the 8x and the 3x making 5x, the equation looking like this:

61=6-5x

next you would subtract the 6 from both sides and the equation would look like:

55=-5x

now for the last step you would divide both sides with the -5 resulting in:

-11=x

hopefully i could help!

Here.

55-3x-2x=10

55-5x=10

-55 -55

-5x=-45

divide -5 from each side,

x=9