when you factor that function, this is what you get:

(x-3)(x-4) =0

to solve for x, set each equal to 0

x-3= 0

x=3

x-4=0

x=4

your answers are 3 & 4.

(x – 3)(x – 4) = 0

x – 3 = 0

x = 3

x – 4 = 0

x = 4

To factor look for two numbers that add up to -7 (the number in front of x) and multiply together to give 12 (the constant). This only works if the number in front of x^2 is 1.

2x – 7x = -12 move 12 over

-5x = -12 simplify x

x = -12/-5 = 12/5 solved

possibilities : 12*1,2*6,4*3 all multiple to twelve, only one of these adds to 7

Try this on (x-4)(x-3)= x*x-3x-4x+12=x^2-7x+12

(x-3) * (x-4) = 0

x = 3 or 4

I didn’t know the 2 was suppose to mean squared.