Is y=square root of (x+1) a function and why? And what is the domain and range of the equation?

Top 2 Answers

A few days ago

John V

Favorite Answer

I will assume that you want to stay in the realm of real numbers only. So for y = sqrt(x+1), y must be >=0, implying that x>= -1. So y=sqrt(x+1) is a function, for x in [-1, + infinity), the domain. The range is [0, + infinity). And it is a function since there is a one-to-one mapping of the domain and range values.

A few days ago

leah p

Yes it is a function. It has only one y value for each x value. The domain is that you can not have a 0 or negative under the square root. The only way you will get that is if x =-1 so X can not be any number below -1. [-1,infinity) is domain

Range is because this is a square root adn you are dealing with real numbers you can not have imaginary answers or negative. The smallest answer you can get with the minimum x which is -1 is square root of -1+1. Which give you 0. So y can be all values 0 and greater. R=[0, infinity)

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Is y=square root of (x+1) a function and why? And what is the domain and range of the equation?

Is y=square root of (x+1) a function and why? And what is the domain and range of the equation?

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