square root of :

(first x minus second x) squared

plus

(first y minus second y) squared

so it would be:

square root of:

20 squared + -12 squared

so that would be:

square root of 400 plus 144

that is square root of 544 which is 23.3 to the nearest tenth, so you were pretty close.

btw got the answer via square root(12^2+20^2) 12 being the y distance and 20 being the x distance.

Delta x is 20. Delta y is 12. What we need to do is the pythagorean theorem. 20^2 + 12^2 is 544. You need to find the square root of this, which is 23.3238… The distance needs to be found to the nearest TENTH, which would yield an answer of 23.3, not 23. But you were EXTREMELY close! 🙂

C and D are the acute vertices of a right triangle whose shorter sides are 20 and 12

sqrt( 20 ^ 2 + 12 ^ 2 ) = 23.3