A few days ago
emando16

If a line contains the points (4, 19) and (-3, 5), what is the slope of a line perpendicular to it?

If line AB contains the points (4, 19) and (-3, 5), what is the slope of a line perpendicular to line AB?

Top 3 Answers
A few days ago
buoisang

Favorite Answer

tip:

1. find slope for the line AB, say m1

2. the slope of the line perpendicular to AB is

m2 = – 1/(m1)

tip: to find slope of line passing A(4,19) and B(-3,5)

slope m1= (yB -yA) / (xA – xB)

where

A(xA, yA) = A(4,19)

B(xB, yB) = B(-3,5)

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circle centered at the origin runs through the point (9, 12). What is the radius of the circle?

tip: radius of the circle at origin running through the point(x,y)

radius = sqrt(x^2, y^2)

radius = sqrt (9^2 + 12^2) = sqrt(81 + 144)

radius = sqrt(225) = 15

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4 years ago
Anonymous
First, enable’s locate the slope of AB. Slope is the replace in y over the replace in x, so: (19 – 5)/(4 – -3) (19-5)/(4+3) 14/7 2 The slopes of perpendicular lines are unfavourable reciprocals of another. So, take 2, make it unfavourable (-2), and take the reciprocal: -a million/2.
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A few days ago
youarestupid(;
1. -1/2

find the slope of line AB, then find the number that when the nunbers are multiplied, they equal -1.

2. 15

use the distance formula to find distance between center & origin .

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