(x-4)^2 + (y+3)^2 = 25 (25 is 5^2)

set x=0 —-has to be on x axis and you get

(16 + y^2 + 6y +9 = 25

subtracting 25 from both sides, you get

y^2+6y = 0

or

y(y+6) = 0 thus the answers are x=0, y=0

and x=0, y=-6

#2

graphing this triangle and looking at it, I see the following

the base goes from (0,0) to (6,0) and its midpoint would be at (3,0). you can then use the distance formula to find the length from (4,4) to (3,0). You now need to use the midpoint formula to find the midpoint of the line from (6,0) to (4,4) and from (0,0) to (6,0). Once you have this, you can use the distnace formula again to find the length of the segment from it’s opposite vertex.

Formulas

midpoint formula x = (x1 + x2)/2 y = (y1 + y2)/2

distance formula d = sqrt ((x2-x1)^2+ (y2-y1)^2)

Note: in both formulas, either point can be (x1,y1) with the second point being (x2,y2)

if you have trouble deciphering distance formula, see web site: http://www.hsunlimited.com/math-lessons/topic/Distance-Formula

Hope this helps

25=(x-4)^2 + (0-(-3)^2)

25= (x^2-8x+16 +9)

25=(x^2-8x+25)

0=x^2-8x

0=x(x-8)

x=0 or x=8

So the points are (0,0) and (8,0)