I need help with my TRIG homework! please!?

[1+cosx] OVER [1-cosx] = (cscx + cotx)^2

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A few days ago

Anonymous

Favorite Answer

Multiply numerator and denominator by 1 + cos(x):

(1 + cos(x)) / (1 – cos(x))

= (1 + cos(x))^2 / (1 – cos(x))(1 + cos(x))

= (1 + cos(x))^2 / (1 – cos^2(x))

= (1 + cos(x))^2 / sin^2(x)

= [ (1 + cos(x)) / sin(x) ]^2

= [ (1/sin(x) + cos(x)/sin(x) ]^2

= (cosec(x) + cot(x))^2.

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