I need help with my math homework?
A steamboat went 8 miles upstream in 1 hour. The return trip took only 30 minutes. Assum that the speed of the current and the direction were constant during both parts of the trip. Find the speed of the boat in still water and the speed of the current.
Please just tell me how to do that problem. I’ll try to figure out the answer myself 🙂
Favorite Answer
let c be the speed of the current
30 min = .5hr
when travel upstream, the speed of the boat is b – c. It takes 1hr to travel 8 miles.
When travel downstream, the speed of the boat is b + c. It takes the boat .5hr to travel 8miles.
distance = speed * time
upstream
8 = (b – c) * 1
8 = b – c
downstream
8 = ( b + c) * .5
16 = b + c
16 = b + c
8 = b – c
—————-
24 = 2b
b = 12
16 = 12 + c
c = 4
so the speed of the boat in still water is 12 mi/hr
speed of the current 4 mi/hr
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles