1) CD is a line segment, DH is connected to CD at point D. R is a point slightly away from either line.

2) Draw a rectangle as the plane Q, put points K and H on it somewhere.

3) You may have mis typed this one, it does not m;ake sense.

4) Here is what I drew, horizontal line UP, the intersecting line RS, I made Rs the edge of a parallelogram to look like a plane.

5) you don’t say where E and F are in relation to the other points

6) Draw line e as a horizontal line.

Then like railroad ties draw the perpendicular line as follows. First is line b intersection at X, then line d intersecting at Z. Next make the distance to the next line equal to XZ and draw line a intersecting at W put line c the same distance away as line b.Good luck, hope this helps.

the growth of (a + b + c)^2 is given by using (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) ______ (a million) For a triangle, the sum of two components > third side. a + b > c, b + c > a, c + a > b those may well be written as: b > c – a, c > a – b, a > b – c Squaring the two side: b^2 > (c – a)^2, c^2 > (a – b)^2, a^2 > (b – c)^2 including the two components of those inequalities and after some algebraic manipulations 2(ab + bc + ca) > a^2 + b^2 + c^2 _________ (2) For any 3 arbitrary not unavoidably distinctive genuine numbers a,b,c: (a – b)^2 ? 0, (b – c)^2 ? 0, (c – a)^2 ? 0 increasing and including and after some algebraic manipulations a^2 + b^2 + c^2 ? ab + bc + ca _________ (3) Combining (a million) and (2) (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) (a + b + c)^2 < 2(ab + bc + ca) + 2(ab + bc + ca) (a + b + c)^2 < 4(ab + bc + ca) [(a + b + c)^2]/4 < (ab + bc + ca) _______ (4) Combining (a million) and (3) (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) (a + b + c)^2 ? (ab + bc + ca) + 2(ab + bc + ca) (a + b + c)^2 ? 3(ab + bc + ca) [(a + b + c)^2]/3 ? (ab + bc + ca) ________ (5) Combining (4) and (5) [(a + b + c)^2]/4 < (ab + bc + ca) ? [(a + b + c)^2]/3 on account that a + b + c = 6, (6^2)/4 < (ab + bc + ca) ? (6^2)/3 9 < (ab + bc + ca) ? 12 P.S.: For middle schoolers this could by no skill be extremely undertaking-free, somewhat i could say it may be puzzling, as they could not have the skill to hyperlink the geometry and genuine huge type concept on the comparable time. the assumption approximately direct application of the assumption A.M. ? G.M. ? H.M. could be deceptive for this reason.