A few days ago
ckroush

I need help factoring this expression…?

Here is the expression:

(x^2+1)^2 3(2x^3+5)^2 (6x^2) + (2x^3+5)^3 (2) (x^2+1) (2x)

I’ve come up with several things but I was never good when it came to algebra material. Please tell me how you got the answer because I need to learn this stuff.

Top 1 Answers
A few days ago
Golis

Favorite Answer

First you figure out the powers (squares, etc)

(x^2 + 1)^2 = (x^2+1)(x^2+1) = (x^4 + 2x^2 + 1) (right… think Foil method)

(2x^3 + 5)^2 = (2x^3 + 5)(2x^3 + 5)

= (4x^6 + 20x^3 + 25)

(2x^3 + 5) ^3 = (2x^3 + 5) (2x^3 + 5) (2x^3 + 5)

=(2x^3 + 5) (4x^6 + 20x^3 + 25)

=(4x^9 + 60x^6 + 150x^3 + 125)

ok..

Next step put it all back into one phrase

(x^4 + 2x^2 + 1) 3 (4x^6 + 20x^3 + 25) (6x^2) + (4x^9 + 60x^6 + 150x^3 + 125) 2 (x^2+1) (2x)

Work each side of the plus separately in chunks (sometimes doing them out of order will help such as the 3 and the 6x^2

left side:

(x^4 + 2x^2 + 1) 3 (4x^6 + 20x^3 + 25) (6x^2)

(x^4 + 2x^2 + 1) (4x^6 + 20x^3 + 25) (18x^2)

(x^4 + 2x^2 + 1) (72x^8 + 360x^5 + 450x^2)

(now the fun part… multiplying the three against the three… no easy way, just have to do it)

72x^12 + 360x^9 + 450 x^6

+144x^10 + 720x^7 + 900x^4

+ 72x^8 + 360x^5 + 450x^2

ok rinse and repeat with the right side from above

(4x^9 + 60x^6 + 150x^3 + 125) 2 (x^2+1) (2x)

(4x^9 + 60x^6 + 150x^3 + 125) (4x^3+4x)

NOW… I am not going to finish the final bit, because you should be on track to finishing this equation, but see how breaking it into steps has made this simpler

look what we are left with:

72x^12 +144x^10 + 360x^9 + 72x^8 + 720x^7 + 450 x^6 + 360x^5 + 900x^4 + 450x^2 + (4x^9 + 60x^6 + 150x^3 + 125) (4x^3+4x)

Don’t be daunted by a nasty equation, just take it one tiny bite at a time.

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