A few days ago
I have done my Physics homework; however, I am confused about one problem. Can someone explain it to me?
Consider an airplane that normaly has an airspeed of 100 km/h in a 100 km/h crosswind from blowing west to east. Calculate its ground velocity when its nose is pointed north in the crosswind.
please help me by explaining this to me. it would really be appreciated!
Top 2 Answers
A few days ago
Favorite Answer
it is flying 100km/h north relative to the air plus
it is blown 100km/h east relative to the ground
so since east and north are at right angles you use pythagoras theorem to calculate the ground velocity
where the velocity is the hypotenuse and the other two sides are both 100km/h
so
v = √(100^2 + 100^2) = 100√2 ≈ 141km/h
and
tanθ = 100/100 = 1
so
θ = arctan1 = 45°
so v = 141km/h northeast relative to the ground
.
1
A few days ago
After one hour it will have traveled 100 km to the north, and the wind will have pushed it 100 km to the east. Draw a diagram, note you have a right triangle and solve for the linear distance d it has traveled. Then calculate ground velocity as d km/h.
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