A few days ago
How would you solve this math problem?
im confused I know its easy for some of you but i need help.
The perimeter of a rectangle is 74 inches. The width is 2 inches less than 1/2 the length. What are the dimensions of the rectangle?
Top 2 Answers
A few days ago
Favorite Answer
2L + 2W = 74
W = 1/2*L – 2
2L + 2(1/2*L – 2) = 74
2L + L – 4 = 74
3L = 78
L = 26
W = 11
0
A few days ago
2L + 2W = 74
W = 1/2*L – 2
2L + 2(1/2*L – 2) = 74
2L + L – 4 = 74
3L = 78
L = 26
W = 11
0
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