How to solve this word problem?
a.) Write E, the life of expectancy,as a linear function of t, the number of years since 1960. [Hint: Use(0,51) and (10,55) as data points]
b.)Use the equation in (a) to predict the life expectancy of males in 2010.
Favorite Answer
y = mx + c
where m is the gradient (slope) of the line and c is the y intercept (where the line cuts the y axis or what y is when x is 0).
Your problem asks you to create a similar equation (in terms of E and t).
E = mt + c
The gradient is given by dy/dx (the change in y / the change in x). Since you know two points on the line (0,51) and (10,55), you can calculate the gradient (m).
(55 – 51) / (10 – 0) = 4/10 or 0.4
(change in y) / (change in x)
So we have…
E = 0.4t + c
c is what y will be when x is 0. We know the point (0, 51) so c will be 51. So your final linear equation is…
E = 0.4t + 51
b) We need to know life expectancy in 2010 (or 50 years after 1960) so substitute 50 in for t to get E…
E = 0.4 * 50 + 51
E = 20 + 51
E = 71
So, assuming (and that’s a very big assumption) that life expectancy in Filipino males grows linearly, men in the Phillippines will be living to 71 on average by 2010.
Hope that makes sense!!
2010, t = 50
E = 71
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