A few days ago
How to solve this geometry question?
I have to do test corrections and I just dont understand this one.
Its “If the height of a triangle is (2b+6) while the base is (b+30), find the area of a triangle.”
I came up with the equation ((2b=6)(6+30))/2.
Please can some one explain how to solve this to me.
Top 2 Answers
A few days ago
Favorite Answer
We know A=1/2 x b x h for triangles, right?
So
A=1/2 x (2b+6) x (b+30)
A= b+3 x (b+30)
A= b^2+3b+30b+90
90=b^2 +33b
or A= b^2 +33b+90
0
A few days ago
since the formula for the area of a triangle is half the base times height, your equation would look like this:
1/2(base)(height)=
1/2(b+30)(2b+6)=
(.5b+15)(2b+6)
Now use the FOIL method and you should get:
1b^2+3b+30b+90=
b^2+33b+90
0
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles