How to solve this geometry question?

I have to do test corrections and I just dont understand this one.

Its “If the height of a triangle is (2b+6) while the base is (b+30), find the area of a triangle.”

I came up with the equation ((2b=6)(6+30))/2.

Please can some one explain how to solve this to me.

Top 2 Answers

A few days ago

Lynn A

Favorite Answer

We know A=1/2 x b x h for triangles, right?

A=1/2 x (2b+6) x (b+30)

A= b+3 x (b+30)

A= b^2+3b+30b+90

90=b^2 +33b

or A= b^2 +33b+90

A few days ago

bored♥out♥of♥my♥mind

since the formula for the area of a triangle is half the base times height, your equation would look like this:

1/2(base)(height)=

1/2(b+30)(2b+6)=

(.5b+15)(2b+6)

Now use the FOIL method and you should get:

1b^2+3b+30b+90=

b^2+33b+90

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