A few days ago
Ineira

How to draw a line?

the system is

2x-y=8

x+y=1

the solution is (3,-2)

so if that is the point of interception on the graph

then can i draw the two lines in whichever direction i want so long as they intercept at that point??

Top 4 Answers
A few days ago
Tim

Favorite Answer

put in y=mx+b form:

-y=8-2x

multiply each side by -1 (to get rid of NEGATIVE y)

y=2x-8

where: rise: 2; run: 1 is the slope

and -8 is the y-inercept

and then:

y=-x+1

where: rise: -1; run: 1 is the slope

and 1 is the y-intercept

follow these rules and sketch.

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A few days ago
Anonymous
No, remember to set each part of the system up as y=mx+b. Where m is the slope of the line and b is the y-intercept point.

When you set it up like that you should get y=2x-8 and y=-1x+1.

Have each respective line cross through the y-intercept and have the correct slope and hit the point of interception.

Hope this rings a bell and helps.

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A few days ago
bluekitty1541
those two equations define two specific lines.

solve each equation for y, then choose values for x and calculate the new value of y

the first equation is y = 2x – 8

the second equation is y = -x + 1

make tables of values and plot the points to form the line

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A few days ago
shuaib
no you cant draw the lines as you specified

first you have to draw two lines seperately and then check for intersection point

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