Raise both sides by 2: SQR(x + 14) ^ 2 = (x + 2) ^ 2

so: x + 14 = (x + 2) ^ 2

distribute: x + 14 = x^2 + 4x + 4

combine like terms: 0 = x^2 + 3x – 10

factor: 0 = (x + 5)(x – 2)

therefore: x = -5, x = 2

but, if you plug in the -5, you get 3 = -3 so -5 is a bad answer.

but 2 works so x = 2

sqr rt (x+14)=x+2

its like this:

x+14=(x+2)^2

x+14=x^2+4x+4

x^2+3x-10=0

factorable to:

(x+5)(x-2)=0

so:

x=-5 and x=2

Now if this your problem:In this problem only x is inside sqrt

sqrt of x + 14 =x+2

sqrt of x = x-12

x-sqrt of x -12=0

factorable to:

(sqrt of x -4)(sqrt of x +3)

sqrt of x =4 and sqrt of x=-3

square both sides of both equations you get:

x=16 and x=9 are the answers

You’re question is ambigous.Just choose which it is really.

x+14 = x^2+4x+4

then set it equal to zero, so

x^2+3x-10=0

next factor

(x+5)(x-2)

so your answers are x= -5 and 2

hope i helped!