how do you do this problem?please keep the answer simple and detailed (write the equation in slpoe int -form
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y=mx+b
where m is the slope and b is the y intercept. You already have the slope and a value for y and x. If you plug in those three values you can solve for b. Then you have the equation of your line. Steps are as follows:
y=mx+b
y=(7/3)x+b
11=(7/3)*3 + b
11=7+b
4=b
Then plug back in:
y=(7/3)x +4
Hope this helps.
y = m x + c equ. (1),
where m is the slope of the line (given as 7/3)
and c is the y-intercept (the point at which the line will cross the y-axis),
so adding your data to equation (1) gives:-
y = (7x)/3 + c equ.(2),
you now need to find c to fully define the equation. We known the line passes through (3,11) or (x = 3, y = 11). So if you know insert these values of x and y into equ. (2) and then rearrange to find c, you will have your equation.
Hope this helps 🙂 (I make it 4)
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