A few days ago
how do u graph the set pionts of 3x + 2y= 0 using intercept?
help
Top 3 Answers
A few days ago
Favorite Answer
1. You find the x-intercept by plugging in 0 for y and solving for x.
3x + 2(0) = 0
3x = 0
x = 0
x intercept is (0,0)
2. Find the y-intercept by plugging in 0 for x and solving for y.
3(0) + 2y = 0
2y = 0
y = 0
y intercept is (0,0)
3. Find one more point. You do this by plugging in ANY value(s) for x and finding it’s corresponding y value. ( I chose 2)
3(2) + 2y = 0
6 + 2y = 0
2y = -6
y = -3
plot: (2, -3)
4. Draw the graph with the points you have
0
A few days ago
try to assume values of x nd get the value of y ..
do this 3 times nd u wil get the points..
make the graph on that points..
it will b a straight line graph….
0
A few days ago
dont you have to solve for y first
0
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