A few days ago
Anonymous

How do I do this Algebra 2 problem? (p.s the answer must be in fraction form)?

18 4/7 – 3 11/15 = ???

aka

eighteen and four sevenths minus three and eleven fiftheenths

(sorry, im a bad speller)

Top 4 Answers
A few days ago
siamcatp

Favorite Answer

Ok, first you need to have the fractions with a common denominator.

So in this case multiply 7 times 15 = 105

then multiply 4 times 15=60 and you end up with 18 60/105 for the first mixed fraction.

Then you multiply 11 times 7 = 77 giving you 3 77/105

Since 77 is bigger then 60, borrow one whole from the 18 giving you 17 165/105.

Subtract 3 from 17 =14 and 77 from 165= 88 and you get 14 88/105. Since you can’t reduce it any further that would be your answer.

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A few days ago
HannahCarrietta
Well figure out what each number is in fractional form like 18 4/7 becomes 130/7 – 56/15…

Then figure out when the bottom numbers would be equal so you would multiply 7*15 on the bottom

1950/105- 392/150= 1558/105

Then you make it the smallest fraction that you can…

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A few days ago
san
ok..the given is in mixed number so we will make an improper fraction by (in the first given) we will multiply 7 and 18 and add 4.So we obtain 130 and copy the denominator. JUst do the same in the second given.. so we now have..130/7 minus 56/15..

Since we cant add them directly, find the (least common multiple) LCM first. the LCM of 7 and 15 is 105.. so..105 divided by the denominator times the numerator.. so we can have 105/7*130 =

1950 over LCM. the 2nd given is 105/15*56 = 392 over the LCm..

we obtain now 1950/150 – 392/150 = 1558/150.

thats the answer..

hope you understand my explanation!

GOOd Luck!! 😉

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A few days ago
English Wiz
first we’ll change the imperfect fractions to make it easier to solve:

18x(7/7)+4/7 and 3x(15/15)+11/15

126/7+4/7 and 45/15+11/15

130/7-56/15

and then find a common denomenatory (sorry cant spell)

(15/15)x(130/7)-(56/15)(7/7)

(1950/105)-(392/105)

1558/105

14 88/105

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