helppp? mathh :[[[ B-90 degrees cos A=3/8 how do i get cot A??? :[[?

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A few days ago

MsMath

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I don’t understand what B-90 degrees has to do with the problem.

You do need to know what quadrant angle A is in, so you know whether cotangent is positive or negative.

I’ll assume A is in the first quadrant.

cos A = adjacent / hypotenuse = 3/8

You can find the opposite side using the Pythagorean theorem.

(opp)^2 + 3^2 = 8^2

(opp)^2 + 9 = 64

(opp)^2 = 55

opp = sqrt(55)

cot A = adjacent / opposite = 3/sqrt(55)

the end justifies the means applied to business?

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