A few days ago

Anonymous

Help with Math hw!?

Can anybody please help me in figuring out the answer to this problem, I have a horrible math teacher who doesn’t teach anything so I am so confused. Thanks so much.

A line passes through the points:

(k+3,-2k) and (4,1)

The y-intercept=6

***Find the value of k****

Top 2 Answers

A few days ago

sayamiam

Favorite Answer

The slope of a line is equal to delta y/delta x: m=(y2-y1)/(x2-x1)

Since the y-intercept is 6, the point is (0,6)

So using point 2 and the y-intercept, calculate the slope:

m= (6-1)/(4-0)

So the slope is 5/4.

The equation of a line is y= slope *x + y-intercept.

so the equation is y= 5/4 x +6

Then plug in the point w/ the k’s:

-2k = 5/4 ( k+3) +6

-2k= 5/4k + 15/4 +6

-6= 13/4k +15/4

Multiply by 4:

-24= 13k +15

Isolate k and solve for k:

13k= -39

k= -3

A few days ago

Amber

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Help with Math hw!?

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