East Bound goes 64 mph for X miles so in hours the time taken is

(x miles) / (64 miles / hour)

we know to put the 64 underneath because after the miles cancel, we get ( x / 64 ) hours

West Bound math becomes ( x / 48 ) hours

6 am to 9.30 am is 3 1/2 hours so now we know

(7 / 2) = (x / 64) + ( x / 48) and we are solving for x

well first thing I want to know is what number both

64 (8 x 8) and 48 (8 x 6) have common factorial with… let’s try 8 x 8 x 6 so

we get (7 / 2) = (6x/64*6) + (8x/48+8)

6+8 = 14 which is divisible by 2

(14x/8*8*6) = 7x/8*8*3)

we can divide the whole thing by 7

(1/2) = (x/8*8*3)

We can rearrange the #s

(8*8*3/2) = x

8*4*3 = 96

so let’s check that

6 am going 64 mph east bound takes 96/64

that’s 8*4*3 / 8*4*2 or 3/2 hour or 1.5 so 7.30 am

7.30 am going 48 mph west bound takes 96/48

that’s 8*12 / 8*6 so 2 hours becomes 9.30 am

I am not going to solve them all

You have to learn how to translate word problems into algebraic equivalents, and how to solve those algebraiic equivalents … I know it is hard … that’s why algebra takes a whole year of schooling.