Perhaps the first equation is x^2-4x+4 = -y

Then adding the two equations together give you

x^2-3x+2 = 0= (x-2)(x-1) = 0 or x= 1 and x=2.

Then substitution in the equation y = x-2 give you the intercepts 1,-1 and 2,0

you would use the graph y = x^2 – 4x + 8, as that is the function which when equated to zero is equivalent to the given equation.

x – y = 2 is equivalent to:

y = x – 2

Equating the two values of y to find the intersection:

x^2 – 4x + 8 = x – 2

x^2 – 5x + 10 = 0

The discriminant of x^2 – 5x + 10 is 5^2 – 40 = -15.

The equation has no real roots, and the two graphs do not therefore intersect.