http://www.analyzemath.com/line/Tutorials.html

Hope this helps you understand it more

now ur equation is y=mx+b , m being the slope..put int he slope as -5/3 and put in the x and y values for one of the points and solve

3=-5/3(-3) +b or 3=5+b or b=-2

so the answer is y=-5/3x-2

Now, the solution to ur problem:

here, x1=-3, x2=2, y1=3, y2=-7.

so equation is

(y-3)/(-7-3) = {x-(-3)}/{2-(-3)}

(y-3)/(-10) = (x+3)/5

-10y+30 = 5x+15

30-15 = 5x+10y

5x+10y = 15

5x+10y-15 = 0

5(x+2y-3) = 0

x+2y-3 = 0

OR

x+2y = 3

Hope it helps!

First find m(slope) which is the difference of the y’s/difference of x’s

3-(-7)/-3-2 = 10/-5=-2

Now, y=-2x+b Find b by substituting EITHER set of points for x and y. 3=-2(-3)+b 3=+6+b 3-6=b -3=b

Equation is y=-2x-3