A few days ago
graphing problem algebra HW help please?
x^3 + 5 = 4x^2 + 30x
how do you find out graphically how many solutions there are?
thanks =)
Top 1 Answers
A few days ago
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First, move all the terms to one side of the equation, (i.e. set the equation equal to zero), and then express the equation as, y in terms of x:
x^3 + 5 = 4x^2 + 30x
=> x^3 – 4x^2 – 30x + 5 = 0
=> f(x) = x^3 – 4x^2 – 30x + 5
=> y = x^3 – 4x^2 – 30x + 5
Now graph: y = x^3 – 4x^2 – 30x + 5.
The number of solutions for this equation, is the number of times the graph crosses the x-axis, (in this case, there should be 3 solutions).
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