A few days ago
Geometry help.?
A bug crawls along the outside of a 6.5 cm by 8.5 cm rectangle. STaying 3.5 cm from it all times. What is the perimeter and area to the nearest tenth of a cm squared of the region bounded by the path of the bug? Do I just do the perimeter and area of the rectangle then add the 3.5 ?
Top 2 Answers
A few days ago
Favorite Answer
No…
You ADD 3.5 to Length AND Width and THEN find the boundary…
10×2 + 12×2 = 20+24 = 44cm
10×12 = 120cm^2
0
A few days ago
lxw becomes 10×12 cm, area will be 120cm2 and perimiter=44
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