Find the zeros of the function by factoring or algeraically.?

f(x)=7x^4+14x^3-168^2

Top 2 Answers

A few days ago

Anonymous

Favorite Answer

Do you mean f(x)=7x^4+14x^3-168x^2?

Then factoring out 7x^2 we get f(x)=7x^2(x^2+2x-24).

Then, solving quadratic equation x^2+2x-24=0, we get x=-6, x=4. Therefore, the zeros are 0, 0, -6, 4.

A few days ago

cidyah

Factor out first:

7x^4+14x^3+168x^2=7x^2(x^2+2x+24)

now factor x^2+2x+24

=(x^2+6x-4x+24)=(x+6)(x-4)

Final answer: 7x^2(x+6)(x-4)

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