find the sideof a sqare with an area of 16z^2 – 24z + 9?

what numerical value must z be greater than for such a square to exist?

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A few days ago

navy_bison

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16z^2 – 24z + 9

16 x 9 = 144

-12 x -12 = 144 and -12 + -12 = -24

16z^2 -12z -12z + 9 “AC” method

-4z(-4z + 3) + 3(-4z +3) factor by GCF

(-4z + 3)(-4z + 3) = 0 Factor by grouping

z must be less than -4/3

if z were -4/3 then z would equal zero, thus no square

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