A few days ago
find the derivative of the given function y=2/x^2?
I know this is a easy one, but I forget how to do it. The text book shows easier examples and harder ones. I am studying for a quiz, I know the answer ( -4/x^3) but I would like to know the thought process. Thanks alot.
Top 3 Answers
A few days ago
Favorite Answer
Rewrite as 2x^-2
Multiply 2 by -2 and decrease the exponent by 1: -4x^-3
Move x^-3 to the denominator to make it positive: -4/x^3
1
A few days ago
u = 2 (numerator)
v = x^2 (denominator)
du = 0 (derivative of numerator)
dv = 2x (derivative of denominator)
[v (du) – u (dv)] / v^2
= [x^2 (0) – 2 (2x)] / x^4
= [0 – 4x] / x^4
= -4x / x^4
factor it, you will get:
= x (-4) / x^4
cancel the x in the numerator and subtract 1 in the exponent of the denominator, you will get -4/x^3.
0
A few days ago
if it’s y = 2/(x^2)
y’ = [(x^2)(0) – (2)(2x)]/(x^4)
y’ = (-4x)/(x^4) = -4/(x^3)
quotient rule
bottom times derivitive of top minus top times derivative of the bottom over the bottom squared
0
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