A few days ago
Find linear function f(x) that satisfies f(1)= 5, and has a graph that is perpendicular to the line 8x-2y=3?
Find linear function f(x) that satisfies f(1)= 5, and has a graph that is perpendicular to the line 8x-2y=3?
Top 2 Answers
A few days ago
Favorite Answer
In standard form, the line is y = 4x – 3/2. So the slope of f(x) is -1/4, so f(x) is given by y = -x/4 + c.
Plug in x=1, y=5 giving 5 = -1/4 + c, so c = 5 + 1/4 = 21/4.
Solution: f(x) = -x/4 + 21/4
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A few days ago
the slope of the line is perpendicular to the slope of the given line. Therefore, the slope of the line required is (-) 1/ (-8/-2).
So the perpendicular slope is -.25 and the point of the line is given as being (1,5).
So then using point-slope form, plug in the numbers to get:
y-5= -.25 (x-1)
If you wanted to put it into y-intercept, then it is:
y= -.25x +4.75
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