EASY domain and range questions?
1) y = 5 / (x+5)
2) y = 2 sqrt(x^2 -1)
My teacher says these are easy, but I do need help. Remember to give an explanation. Thanks!
Favorite Answer
y = 5 / (x + 5) is a valid formula for any value of x except x = -5. This is not valid, as it makes the denominator zero. The domain is therefore:
(-infinity, 0) U (0, infinity).
Find x in terms of y:
y(x + 5) = 5
x + 5 = 5 / y
x = (5/y) – 5
This is valid for any value of y except y = 0.
The range is:
(-infinity,0) U (0, infinity).
2.
y = 2sqrt(x^2 – 1) is valid provided x^2 – 1 >= 0.
Negative numbers do not have square roots.
x^2 – 1 >= 0 means x >= 1 or x <= -1. The domain is thererfore: (-infinity, -1] U [1, infinity). By letting x approach infinity or - infinity, you can make y as large as you like. Because the square root is always +ve or 0, y cannot be less than 0. The range is therefore: [0, infinity).
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