Division w/ Exponents.?

[a^(5/3)b^(-1/2)c^(2/5)]^3

divided by

[a^(-1/2)b^(1/3)c^(3/5)]^(-3)

is the answer:

a to the fourth times (2c)^(6/5) all over b^(5/6)

or can it be simplified even more?

thnx

Top 1 Answers

A few days ago

Anonymous

Favorite Answer

The numerator is:

[a^(5/3) b^(-1/2) c^(2/5)]^3

= a^5 b^(-3/2) c^(6/5) …..(1)

The denominator is:

[a^(-1/2)b^(1/3)c^(3/5)]^(-3)

which is equivalent to:

[a^(-1/2)b^(1/3)c^(3/5)]^3

in the numerator.

Simplifying this gives:

a^(-3/2) b c^(9/5) …(2)

Multiplying (1) by (2) gives:

a^(5 – 3/2) b^(1 – 3/2) c^((9 + 6)/5)

= a^((10 – 3)/2 b^((2 – 3)/2) c^(15/5)

= a^(7/2) b^(-1/2) c^3

= a^(7/2) c^3 / b^(1/2).

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