A few days ago
Chem Help- Clever chemist needed. Please….?
Im stuck on this titration calculation q and i cant seem to work it out correctly. Please could someone work it out and show the step by step working. Thanks so much, i will choose best answer and ur help is greatly appreciated!
Calculate the concentration of a solution of sodium hydroxide given that 25 cm cubed of it required 18.8 cm cubed of 0.0500 mol dm cubed H2s04
Balanced equation:
H2s04+2NaOH (arrow sign) Na2s04+ 2h20
Top 2 Answers
A few days ago
Favorite Answer
H2S04+2NaOH ——–> Na2S04+ 2H20
V(NaOH) = 25cm^3 =25×10^-3 L
V(H2SO4) = 18.8cm^3 = 18.8×10^-3L
C(H2SO4) = 0.0500mol/L
note: 1dm^3 = 1L and 1cm^3 = 10^-3L
then
n(NaOH) = 2 x n(H2SO4) from the chemical equation
substitute n = cv then
C(NaOH) x V(NaOH) = 2 x C(H2SO4) x V(H2SO4)
rearrange gives
C(NaOH) = 2 x C(H2SO4) x V(H2SO4) / V(NaOH)
= 2 x 0.0500 x 18.8×10^-3 / 25×10^-3
= 2 x 0.0500 x 18.8 / 25
= 0.0752 mol/L
.
1
4 years ago
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