A few days ago
Checking a Factoring Prob?
Factor completely.
(x^2+6)^(7/2) + 2x(x^2+6)^(5/2) + x^2(x^2+6)^(3/2)
this is what I ended up with:
x^7 + 2x^6 + x^5 + x^2(6^1.5) + 2x(6^2.5) + 6^3.5
I think it could possibly be factored more but I’m not sure how. Thanks for any serious help.
Top 2 Answers
A few days ago
Favorite Answer
ther is a math website that can help you understand and figure problems out. it is called webmath.com give it a try.
good luck
0
A few days ago
There is a factor of (x^2+6) in each term, so
(x^2+6)(7/2 +2x*5/2 + x^2*3/2)
Now simplify the terms in the second bracket:
(x^2+6)(7/2 + 5x + 3x^2/2)
Pretty certain it won`t factorise any further.
Hope this helps, Twiggy
Yes, just had another look, and it does factorise further:
(x^2+6)(3x^2/2 + 5x + 7/2)
=(x^2 + 6)(3x/2 + 7/2)(x + 1)
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