Can you help me solve these word problems?
Two planes leave Chicago–one traveling due east and the other due west.The first travels 100 miles per hour faster than the second.How long will it be until they are 2,000 miles apart?(To me it seems like there is not enough info to solve but I could be wrong)
Favorite Answer
2x = loss
10,000 + x – 2x = 8,000
10,000 – x = 8,000
-x = -2,000
x = 2,000
gain $2,000 ; loss $4,000
———————————
x = speed of 2nd
x + 100 = speed of 1st
y = time for both
xy + (x + 100)y = 2000
(x + x + 100)y = 2000
(2x + 100)y = 2000
(x + 50)y = 1000
I think you are right. Something seems to be missing.
Let the gain be x $ and loss be $ y
So according to the question
10000 + gain – loss = 8000
10000 + x – 2x = 8000
10000 – x = 8000
x = 10000 – 8000 = 2000
Therefore the gain was $2000 and loss was $4000
Sol 2:
One bit of information is missing. Either speed should be specified or the time taken to cover this distance should be given
2) You are right — there isn’t enough information given.
Use the formula: distance = rate * time
distance = 2000 miles
rate of second = x
rate of first = x + 100
total rate = 2x + 100
time = t
2000 = (2x+100)*t
Two unknowns (two variables) means that we need a second equation to solve, but there isn’t any more information given.
$10,000+2,000=$12,000
2,000 X 2= 4,000
12, 000-4,000= $8,000
for the second
the formual for speed is s=d/t
ill keep working at it
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