can someone please help with a pre-calc question?
Favorite Answer
t = -2
x = 3 – (-2)^2
x = 3 – 4
x = -1
y = 1 + 2(-2)
y = 1 – 4
y = -3
————————–
t = -1
x = 3 – (-1)^2
x = 3 – 1
x = 2
y = 1 + 2(-1)
y = 1 – 2
y = -1
————————
t = 0
x = 3 – (0)^2
x = 3
y = 1 + 2(0)
y = 1
——————————
t = 1
x = 3 – (1)^2
x = 3 – 1
x = 2
y = 1 + 2(1)
y = 1 + 2
y = 3
———————————
t = 2
x = 3 – (2)^2
x = 3 – 4
x = -1
y = 1 + 2(2)
y = 1 + 4
y = 5
table:
t ……… x ………y
-2 ….. -1 ……. -3
-1 ….. 2 …….. -1
0……. 3 ………1
1 …… 2 ……… 3
2 ……-1 ……… 5
now just plug the points in a graph and connect the dots.
Graph:
the graph is represented by two equations:
y = 1 + 2√(3 – x)
and
y = 1 – 2√(3 – x)
where the domain is x: [-1 , 3]
example, start at t= -2. plug in for the x equation. x=3-(-2)^2=-1. then do it for y. y=1+2(-2)=-1. so your first point is (-1,-1). graph that, and do the same for the rest of the values of t.
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